总述:本次共解1题。其中
☆算术计算1题
〖1/1算式〗
作业:求算式 1-0.35×√(1130.8/284816.67)+0.35×√(1130.8/284816.67)×((-27.3)/72.4) 的值.
题型:数学计算
解:
1-0.35×√(1130.8/284816.67)+0.35×√(1130.8/284816.67)×((-27.3)/72.4)
=1-0.35×√0.00397+0.35×√(1130.8/284816.67)×((-27.3)/72.4)
=1-0.35×√0.00397+0.35×√0.00397×((-27.3)/72.4)
=1-0.35×√0.00397+0.35×√0.00397×((-27.3)/72.4)
=1-0.35×√0.00397+0.35×√0.00397×(-0.377072)
=1-0.35×0.063008+0.35×√0.00397×-0.377072
=1-0.35×0.063008+0.35×0.063008×-0.377072
=1-0.022053+0.35×0.063008×(-0.377072)
=1-0.022053+0.022053×(-0.377072)
=1-0.022053+(-0.008316)
=0.977947+(-0.008316)
=0.969631 答案:1-0.35×√(1130.8/284816.67)+0.35×√(1130.8/284816.67)×((-27.3)/72.4)=0.969631你的问题在这里没有得到解决?请到 热门难题 里面看看吧!