总述:本次共解1题。其中
☆算术计算1题
〖1/1算式〗
作业:求算式 1-0.35×√(1130.8/284816.67)+0.35×√(1130.8/284816.67)×(0) 的值.
题型:数学计算
解:
1-0.35×√(1130.8/284816.67)+0.35×√(1130.8/284816.67)×(0)
=1-0.35×√0.00397+0.35×√(1130.8/284816.67)×(0)
=1-0.35×√0.00397+0.35×√0.00397×(0)
=1-0.35×√0.00397+0.35×√0.00397×0
=1-0.35×0.063008+0.35×√0.00397×0
=1-0.35×0.063008+0.35×0.063008×0
=1-0.022053+0.35×0.063008×0
=1-0.022053+0.022053×0
=1-0.022053+0
=0.977947+0
=0.977947 答案:1-0.35×√(1130.8/284816.67)+0.35×√(1130.8/284816.67)×(0)=0.977947你的问题在这里没有得到解决?请到 热门难题 里面看看吧!