总述:本次共解1题。其中
☆算术计算1题
〖1/1算式〗
作业:求算式 1+1/(1300×((80.39+61.25+61.065)/1816.2×10^3+23.3)/(700-35))×((10000/700))^2×1 的值.
题型:数学计算
解:
1+1/(1300×((80.39+61.25+61.065)/1816.2×10^3+23.3)/(700-35))×((10000/700))^2×1
=1+1/(1300×(202.705/1816.2×10^3+23.3)/(700-35))×((10000/700))^2×1
=1+1/(1300×134.909/(700-35))×((10000/700))^2×1
=1+1/(1300×134.909/665)×((10000/700))^2×1
=1+1/263.73188×((10000/700))^2×1
=1+1/263.73188×(14.285714)^2×1
=1+1/263.73188×14.285714^2×1
=1+1/263.73188×204.081624489796013×1
=1+0.003792×204.081624489796013×1
=1+0.773878×1
=1+0.773878
=1.773878 答案:1+1/(1300×((80.39+61.25+61.065)/1816.2×10^3+23.3)/(700-35))×((10000/700))^2×1=1.773878你的问题在这里没有得到解决?请到 热门难题 里面看看吧!