总述:本次共解1题。其中
☆算术计算1题
〖1/1算式〗
作业:求算式 1+1/(1300×((80.39+61.25+54.486)/1816.2×10^3+23.3)/(700-35))×((10000/700))^2×1 的值.
题型:数学计算
解:
1+1/(1300×((80.39+61.25+54.486)/1816.2×10^3+23.3)/(700-35))×((10000/700))^2×1
=1+1/(1300×(196.126/1816.2×10^3+23.3)/(700-35))×((10000/700))^2×1
=1+1/(1300×131.287/(700-35))×((10000/700))^2×1
=1+1/(1300×131.287/665)×((10000/700))^2×1
=1+1/256.651278×((10000/700))^2×1
=1+1/256.651278×(14.285714)^2×1
=1+1/256.651278×14.285714^2×1
=1+1/256.651278×204.081624489796013×1
=1+0.003896×204.081624489796013×1
=1+0.795102×1
=1+0.795102
=1.795102 答案:1+1/(1300×((80.39+61.25+54.486)/1816.2×10^3+23.3)/(700-35))×((10000/700))^2×1=1.795102你的问题在这里没有得到解决?请到 热门难题 里面看看吧!