总述:本次共解1题。其中
☆算术计算1题
〖1/1算式〗
作业:求算式 1.0×1.0×1.1×0.45×10^(-3)×1400×1550×√((2+0.6×0.7948)×√40×0.005189×250) 的值.
题型:数学计算
解:
1.0×1.0×1.1×0.45×10^(-3)×1400×1550×√((2+0.6×0.7948)×√40×0.005189×250)
=1.0×1.0×1.1×0.45×10^(-3)×1400×1550×√((2+0.6×0.7948)×√40×0.005189×250)
=1.0×1.0×1.1×0.45×10^-3×1400×1550×√(2.47688×√40×0.005189×250)
=1.0×1.0×1.1×0.45×10^-3×1400×1550×√20.32175
=1.0×1.0×1.1×0.45×10^-3×1400×1550×4.507965
=1×1×1.1×0.45×0.001×1400×1550×4.507965
=1×1.1×0.45×0.001×1400×1550×4.507965
=1.1×0.45×0.001×1400×1550×4.507965
=0.495×0.001×1400×1550×4.507965
=0.000495×1400×1550×4.507965
=0.693×1550×4.507965
=1074.15×4.507965
=4842.230605 答案:1.0×1.0×1.1×0.45×10^(-3)×1400×1550×√((2+0.6×0.7948)×√40×0.005189×250)=4842.230605你的问题在这里没有得到解决?请到 热门难题 里面看看吧!