总述：本次共解1题。其中
           ☆算术计算1题

〖1/1算式〗
    作业：求算式 (0.5×22+2.4×19.1+2.5×22+20-10×(0.5+2.4+2.5))×0.22-2×0×√0.22+10×(0.5+2.4+2.5) 的值.
    题型：数学计算
    解:
          (0.5×22+2.4×19.1+2.5×22+20-10×(0.5+2.4+2.5))×0.22-2×0×√0.22+10×(0.5+2.4+2.5)
        =(0.5×22+2.4×19.1+2.5×22+20-10×5.4)×0.22-2×0×√0.22+10×(0.5+2.4+2.5)
        =77.84×0.22-2×0×√0.22+10×(0.5+2.4+2.5)
        =77.84×0.22-2×0×√0.22+10×5.4
        =77.84×0.22-2×0×0.469042+10×5.4
        =17.1248-2×0×0.469042+10×5.4
        =17.1248-0×0.469042+10×5.4
        =17.1248-0+10×5.4
        =17.1248-0+54
        =17.1248+54
        =71.1248
    答案:(0.5×22+2.4×19.1+2.5×22+20-10×(0.5+2.4+2.5))×0.22-2×0×√0.22+10×(0.5+2.4+2.5)=71.1248

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