总述:本次共解1题。其中
☆算术计算1题
〖1/1算式〗
作业:求算式 (0.5×22+2.4×19.1+2.5×22+20-10×(0.5+2.4+2.5))×0.22-2×0×√0.22+10×(0.5+2.4+2.5) 的值.
题型:数学计算
解:
(0.5×22+2.4×19.1+2.5×22+20-10×(0.5+2.4+2.5))×0.22-2×0×√0.22+10×(0.5+2.4+2.5)
=(0.5×22+2.4×19.1+2.5×22+20-10×5.4)×0.22-2×0×√0.22+10×(0.5+2.4+2.5)
=77.84×0.22-2×0×√0.22+10×(0.5+2.4+2.5)
=77.84×0.22-2×0×√0.22+10×5.4
=77.84×0.22-2×0×0.469042+10×5.4
=17.1248-2×0×0.469042+10×5.4
=17.1248-0×0.469042+10×5.4
=17.1248-0+10×5.4
=17.1248-0+54
=17.1248+54
=71.1248 答案:(0.5×22+2.4×19.1+2.5×22+20-10×(0.5+2.4+2.5))×0.22-2×0×√0.22+10×(0.5+2.4+2.5)=71.1248你的问题在这里没有得到解决?请到 热门难题 里面看看吧!