总述:本次共解1题。其中
☆算术计算1题
〖1/1算式〗
作业:求算式 (0.5×22+2.4×19.1+20-10×(0.5+2.4))×0.33-2×0×√0.33+10×(0.5+2.4) 的值.
题型:数学计算
解:
(0.5×22+2.4×19.1+20-10×(0.5+2.4))×0.33-2×0×√0.33+10×(0.5+2.4)
=(0.5×22+2.4×19.1+20-10×2.9)×0.33-2×0×√0.33+10×(0.5+2.4)
=47.84×0.33-2×0×√0.33+10×(0.5+2.4)
=47.84×0.33-2×0×√0.33+10×2.9
=47.84×0.33-2×0×0.574456+10×2.9
=15.7872-2×0×0.574456+10×2.9
=15.7872-0×0.574456+10×2.9
=15.7872-0+10×2.9
=15.7872-0+29
=15.7872+29
=44.7872 答案:(0.5×22+2.4×19.1+20-10×(0.5+2.4))×0.33-2×0×√0.33+10×(0.5+2.4)=44.7872你的问题在这里没有得到解决?请到 热门难题 里面看看吧!