总述:本次共解1题。其中
☆算术计算1题
〖1/1算式〗
作业:求算式 1+1/(1300×((164.06+125+54.486)/1816.2+23.3)/(700-35))*((10000/700))^2×1 的值.
题型:数学计算
解:
1+1/(1300×((164.06+125+54.486)/1816.2+23.3)/(700-35))*((10000/700))^2×1
=1+1/(1300×(343.546/1816.2+23.3)/(700-35))*((10000/700))^2×1
=1+1/(1300×23.489156/(700-35))*((10000/700))^2×1
=1+1/(1300×23.489156/665)*((10000/700))^2×1
=1+1/45.918651*((10000/700))^2×1
=1+1/45.918651*(14.285714)^2×1
=1+1/45.918651*14.285714^2×1
=1+1/45.918651*204.081624489796013×1
=1+0.021778*204.081624489796013×1
=1+4.44449×1
=1+4.44449
=5.44449 答案:1+1/(1300×((164.06+125+54.486)/1816.2+23.3)/(700-35))*((10000/700))^2×1=5.44449你的问题在这里没有得到解决?请到 热门难题 里面看看吧!