总述:本次共解1题。其中
☆算术计算1题
〖1/1算式〗
作业:求算式 1+1/(1300×((0+23.3))/(700-35))*((10000/700))^2×1.653 的值.
题型:数学计算
解:
1+1/(1300×((0+23.3))/(700-35))*((10000/700))^2×1.653
=1+1/(1300×(23.3)/(700-35))*((10000/700))^2×1.653
=1+1/(1300×23.3/(700-35))*((10000/700))^2×1.653
=1+1/(1300×23.3/665)*((10000/700))^2×1.653
=1+1/45.548872*((10000/700))^2×1.653
=1+1/45.548872*(14.285714)^2×1.653
=1+1/45.548872*14.285714^2×1.653
=1+1/45.548872*204.081624489796013×1.653
=1+0.021954*204.081624489796013×1.653
=1+4.480408×1.653
=1+7.406114
=8.406114 答案:1+1/(1300×((0+23.3))/(700-35))*((10000/700))^2×1.653=8.406114你的问题在这里没有得到解决?请到 热门难题 里面看看吧!