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〖1/1算式〗
作业:求算式 (0.436^2*ln(0.8*11.48/47.97/0.436))/(1-0.436)^2/ln(0.2*11.48/4.074/(1-0.436)) 的值.
题型:数学计算
解:
(0.436^2*ln(0.8*11.48/47.97/0.436))/(1-0.436)^2/ln(0.2*11.48/4.074/(1-0.436))
=(0.436^2*ln0.439112)/(1-0.436)^2/ln(0.2*11.48/4.074/(1-0.436))
=-0.156449/(1-0.436)^2/ln(0.2*11.48/4.074/(1-0.436))
=-0.156449/0.564^2/ln(0.2*11.48/4.074/(1-0.436))
=-0.156449/0.564^2/ln(0.2*11.48/4.074/0.564)
=-0.156449/0.564^2/ln0.999245
=-0.156449/0.564^2/-0.000755
=-0.156449/0.318096/(-0.000755)
=-0.49183/(-0.000755)
=651.430464 答案:(0.436^2*ln(0.8*11.48/47.97/0.436))/(1-0.436)^2/ln(0.2*11.48/4.074/(1-0.436))=651.430464你的问题在这里没有得到解决?请到 热门难题 里面看看吧!