总述：本次共解1题。其中
           ☆算术计算1题

〖1/1算式〗
    作业：求算式 1/√(25×((1.330391*103.34*0.112)^2+1)÷(1.330391^2+1)÷1.330391^2÷(0.25*1.330391^2+1)÷((1.330391*103.34)^2+1)) 的值.
    题型：数学计算
    解:
          1/√(25×((1.330391*103.34*0.112)^2+1)÷(1.330391^2+1)÷1.330391^2÷(0.25*1.330391^2+1)÷((1.330391*103.34)^2+1))
        =1/√(25×(15.398052^2+1)÷(1.330391^2+1)÷1.330391^2÷(0.25*1.330391^2+1)÷((1.330391*103.34)^2+1))
        =1/√(25×238.100005÷(1.330391^2+1)÷1.330391^2÷(0.25*1.330391^2+1)÷((1.330391*103.34)^2+1))
        =1/√(25×238.100005÷2.76994÷1.330391^2÷(0.25*1.330391^2+1)÷((1.330391*103.34)^2+1))
        =1/√(25×238.100005÷2.76994÷1.330391^2÷1.442485÷((1.330391*103.34)^2+1))
        =1/√(25×238.100005÷2.76994÷1.330391^2÷1.442485÷(137.482606^2+1))
        =1/√(25×238.100005÷2.76994÷1.330391^2÷1.442485÷18902.466953)
        =1/√0.044529
        =1/0.211019
        =4.73891
    答案:1/√(25×((1.330391*103.34*0.112)^2+1)÷(1.330391^2+1)÷1.330391^2÷(0.25*1.330391^2+1)÷((1.330391*103.34)^2+1))=4.73891

你的问题在这里没有得到解决？请到 热门难题 里面看看吧！