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〖1/1算式〗
作业:求算式 115.00×((1+0.0435)^1-1)+(2300+150+20+21.5+104.26)*((1+0.0435)^0.5-1) 的值.
题型:数学计算
解:
115.00×((1+0.0435)^1-1)+(2300+150+20+21.5+104.26)*((1+0.0435)^0.5-1)
=115.00×(1.0435^1-1)+(2300+150+20+21.5+104.26)*((1+0.0435)^0.5-1)
=115.00×0.0435+(2300+150+20+21.5+104.26)*((1+0.0435)^0.5-1)
=115.00×0.0435+2595.76*((1+0.0435)^0.5-1)
=115.00×0.0435+2595.76*(1.0435^0.5-1)
=115.00×0.0435+2595.76*0.021518
=5.0025+2595.76*0.021518
=5.0025+55.855564
=60.858064 答案:115.00×((1+0.0435)^1-1)+(2300+150+20+21.5+104.26)*((1+0.0435)^0.5-1)=60.858064你的问题在这里没有得到解决?请到 热门难题 里面看看吧!