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〖1/1算式〗
    作业：求算式 0.32*14.3*100*3.1416*0.4*0.4*(1-sin(2*180*0.32)/(2*3.1415926*0.32))+(3*0.32-1.25)*300*5.1 的值.
    题型：数学计算
    解:
          0.32*14.3*100*3.1416*0.4*0.4*(1-sin(2*180*0.32)/(2*3.1415926*0.32))+(3*0.32-1.25)*300*5.1
        =0.32*14.3*100*3.1416*0.4*0.4*(1-sin115.2/(2*3.1415926*0.32))+(3*0.32-1.25)*300*5.1
        =0.32*14.3*100*3.1416*0.4*0.4*(1-sin115.2/2.010619)+(3*0.32-1.25)*300*5.1
        =0.32*14.3*100*3.1416*0.4*0.4*0.571345+(3*0.32-1.25)*300*5.1
        =0.32*14.3*100*3.1416*0.4*0.4*0.571345+(-0.29)*300*5.1
        =4.576*100*3.1416*0.4*0.4*0.571345+(-0.29)*300*5.1
        =457.6*3.1416*0.4*0.4*0.571345+(-0.29)*300*5.1
        =1437.59616*0.4*0.4*0.571345+(-0.29)*300*5.1
        =575.038464*0.4*0.571345+(-0.29)*300*5.1
        =230.015386*0.571345+(-0.29)*300*5.1
        =131.418141+(-0.29)*300*5.1
        =131.418141+(-87)*5.1
        =131.418141+(-443.7)
        =-312.281859
    答案:0.32*14.3*100*3.1416*0.4*0.4*(1-sin(2*180*0.32)/(2*3.1415926*0.32))+(3*0.32-1.25)*300*5.1=-312.281859
    注：弧度制

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