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〖1/1算式〗
    作业：求算式 0.32*14.3*1000*3.1416*0.4*0.4*(1-sin(2*180*0.32)/(2*3.1415926*0.32))+(3*0.32-1.25)*300*510 的值.
    题型：数学计算
    解:
          0.32*14.3*1000*3.1416*0.4*0.4*(1-sin(2*180*0.32)/(2*3.1415926*0.32))+(3*0.32-1.25)*300*510
        =0.32*14.3*1000*3.1416*0.4*0.4*(1-sin115.2/(2*3.1415926*0.32))+(3*0.32-1.25)*300*510
        =0.32*14.3*1000*3.1416*0.4*0.4*(1-sin115.2/2.010619)+(3*0.32-1.25)*300*510
        =0.32*14.3*1000*3.1416*0.4*0.4*0.571345+(3*0.32-1.25)*300*510
        =0.32*14.3*1000*3.1416*0.4*0.4*0.571345+(-0.29)*300*510
        =4.576*1000*3.1416*0.4*0.4*0.571345+(-0.29)*300*510
        =4576*3.1416*0.4*0.4*0.571345+(-0.29)*300*510
        =14375.9616*0.4*0.4*0.571345+(-0.29)*300*510
        =5750.38464*0.4*0.571345+(-0.29)*300*510
        =2300.153856*0.571345+(-0.29)*300*510
        =1314.181405+(-0.29)*300*510
        =1314.181405+(-87)*510
        =1314.181405+(-44370)
        =-43055.818595
    答案:0.32*14.3*1000*3.1416*0.4*0.4*(1-sin(2*180*0.32)/(2*3.1415926*0.32))+(3*0.32-1.25)*300*510=-43055.818595
    注：弧度制

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