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〖1/1算式〗
    作业：求算式 5517.2×4911.5/4*((1+(2×((201.5)^2-125^2))/(4911.5)^2)/(1+(4×125)/(3×4911.5))-(4×675)/4911.5) 的值.
    题型：数学计算
    解:
          5517.2×4911.5/4*((1+(2×((201.5)^2-125^2))/(4911.5)^2)/(1+(4×125)/(3×4911.5))-(4×675)/4911.5)
        =5517.2×4911.5/4*((1+(2×(201.5^2-125^2))/(4911.5)^2)/(1+(4×125)/(3×4911.5))-(4×675)/4911.5)
        =5517.2×4911.5/4*((1+(2×24977.25)/(4911.5)^2)/(1+(4×125)/(3×4911.5))-(4×675)/4911.5)
        =5517.2×4911.5/4*((1+49954.5/(4911.5)^2)/(1+(4×125)/(3×4911.5))-(4×675)/4911.5)
        =5517.2×4911.5/4*((1+49954.5/4911.5^2)/(1+(4×125)/(3×4911.5))-(4×675)/4911.5)
        =5517.2×4911.5/4*(1.002071/(1+(4×125)/(3×4911.5))-(4×675)/4911.5)
        =5517.2×4911.5/4*(1.002071/(1+500/(3×4911.5))-(4×675)/4911.5)
        =5517.2×4911.5/4*(1.002071/(1+500/14734.5)-(4×675)/4911.5)
        =5517.2×4911.5/4*(1.002071/1.033934-(4×675)/4911.5)
        =5517.2×4911.5/4*(1.002071/1.033934-2700/4911.5)
        =5517.2×4911.5/4*0.419453
        =27097727.8/4*0.419453
        =6774431.95*0.419453
        =2841555.804723
    答案:5517.2×4911.5/4*((1+(2×((201.5)^2-125^2))/(4911.5)^2)/(1+(4×125)/(3×4911.5))-(4×675)/4911.5)=2841555.804723

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