总述:本次共解1题。其中
☆算术计算1题
〖1/1算式〗
作业:求算式 π/4×0.5*((0.45)^2-53*(25/1000)^2)+π/4×0.4375*(20/1000)^2×53 的值.
题型:数学计算
解:
π/4×0.5*((0.45)^2-53*(25/1000)^2)+π/4×0.4375*(20/1000)^2×53
=π/4×0.5*(0.45^2-53*(25/1000)^2)+π/4×0.4375*(20/1000)^2×53
=π/4×0.5*(0.45^2-53*0.025^2)+π/4×0.4375*(20/1000)^2×53
=π/4×0.5*0.169375+π/4×0.4375*(20/1000)^2×53
=π/4×0.5*0.169375+π/4×0.4375*0.02^2×53
=π/4×0.5*0.169375+π/4×0.4375*0.0004×53
=0.785398×0.5*0.169375+π/4×0.4375*0.0004×53
=0.392699*0.169375+π/4×0.4375*0.0004×53
=0.066513+π/4×0.4375*0.0004×53
=0.066513+0.785398×0.4375*0.0004×53
=0.066513+0.343612*0.0004×53
=0.066513+0.000137×53
=0.066513+0.007261
=0.073774 答案:π/4×0.5*((0.45)^2-53*(25/1000)^2)+π/4×0.4375*(20/1000)^2×53=0.073774你的问题在这里没有得到解决?请到 热门难题 里面看看吧!