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☆算术计算1题
〖1/1算式〗
作业:求算式 (11*sqrt(50^2*0.0004^2+1))/(0.0004*sqrt(0.0004^2+1)*sqrt(1+1/16*0.0004^2)*sqrt(1+2500^2*0.0004^2)) 的值.
题型:数学计算
解:
(11*sqrt(50^2*0.0004^2+1))/(0.0004*sqrt(0.0004^2+1)*sqrt(1+1/16*0.0004^2)*sqrt(1+2500^2*0.0004^2))
=(11*sqrt1.0004)/(0.0004*sqrt(0.0004^2+1)*sqrt(1+1/16*0.0004^2)*sqrt(1+2500^2*0.0004^2))
=11.0022/(0.0004*sqrt(0.0004^2+1)*sqrt(1+1/16*0.0004^2)*sqrt(1+2500^2*0.0004^2))
=11.0022/(0.0004*sqrt1*sqrt(1+1/16*0.0004^2)*sqrt(1+2500^2*0.0004^2))
=11.0022/(0.0004*sqrt1*sqrt1*sqrt(1+2500^2*0.0004^2))
=11.0022/(0.0004*sqrt1*sqrt1*sqrt2)
=11.0022/0.000566
=19438.515901 答案:(11*sqrt(50^2*0.0004^2+1))/(0.0004*sqrt(0.0004^2+1)*sqrt(1+1/16*0.0004^2)*sqrt(1+2500^2*0.0004^2))=19438.515901你的问题在这里没有得到解决?请到 热门难题 里面看看吧!