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☆算术计算1题
〖1/1算式〗
作业:求算式 (0.78+2.243*(3^0.5))*(1-0.3)*((0.993+0.18*0.3)--1.06*0.09+1.71*(0.3^3)) 的值.
题型:数学计算
解:
(0.78+2.243*(3^0.5))*(1-0.3)*((0.993+0.18*0.3)--1.06*0.09+1.71*(0.3^3))
=(0.78+2.243*1.732050807568877)*(1-0.3)*((0.993+0.18*0.3)--1.06*0.09+1.71*(0.3^3))
=4.66499*(1-0.3)*((0.993+0.18*0.3)--1.06*0.09+1.71*(0.3^3))
=4.66499*0.7*((0.993+0.18*0.3)--1.06*0.09+1.71*(0.3^3))
=4.66499*0.7*(1.047--1.06*0.09+1.71*(0.3^3))
=4.66499*0.7*(1.047--1.06*0.09+1.71*0.027)
=4.66499*0.7*1.18857
=3.265493*1.18857
=3.881267 答案:(0.78+2.243*(3^0.5))*(1-0.3)*((0.993+0.18*0.3)--1.06*0.09+1.71*(0.3^3))=3.881267你的问题在这里没有得到解决?请到 热门难题 里面看看吧!