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☆算术计算1题
〖1/1算式〗
作业:求算式 (0.78+2.243*(3^0.5))*(1-0.3)*(0.993+0.18*0.3)--1.06*0.09+1.71*(0.3^3) 的值.
题型:数学计算
解:
(0.78+2.243*(3^0.5))*(1-0.3)*(0.993+0.18*0.3)--1.06*0.09+1.71*(0.3^3)
=(0.78+2.243*1.732050807568877)*(1-0.3)*(0.993+0.18*0.3)--1.06*0.09+1.71*(0.3^3)
=4.66499*(1-0.3)*(0.993+0.18*0.3)--1.06*0.09+1.71*(0.3^3)
=4.66499*0.7*(0.993+0.18*0.3)--1.06*0.09+1.71*(0.3^3)
=4.66499*0.7*1.047--1.06*0.09+1.71*(0.3^3)
=4.66499*0.7*1.047--1.06*0.09+1.71*0.027
=3.265493*1.047-(-1.06)*0.09+1.71*0.027
=3.418971-(-1.06)*0.09+1.71*0.027
=3.418971-(-0.0954)+1.71*0.027
=3.418971--0.0954+0.04617
=3.514371+0.04617
=3.560541 答案:(0.78+2.243*(3^0.5))*(1-0.3)*(0.993+0.18*0.3)--1.06*0.09+1.71*(0.3^3)=3.560541你的问题在这里没有得到解决?请到 热门难题 里面看看吧!