总述:本次共解1题。其中
☆算术计算1题
〖1/1算式〗
作业:求算式 0.51*(10*(0.109+2.661*ln1.19))+0.49*(10*(9.436+1.624*ln0.161)) 的值.
题型:数学计算
解:
0.51*(10*(0.109+2.661*ln1.19))+0.49*(10*(9.436+1.624*ln0.161))
=0.51*(10*0.571889)+0.49*(10*(9.436+1.624*ln0.161))
=0.51*5.71889+0.49*(10*(9.436+1.624*ln0.161))
=0.51*5.71889+0.49*(10*6.470006)
=0.51*5.71889+0.49*64.70006
=2.916634+0.49*64.70006
=2.916634+31.703029
=34.619663 答案:0.51*(10*(0.109+2.661*ln1.19))+0.49*(10*(9.436+1.624*ln0.161))=34.619663你的问题在这里没有得到解决?请到 热门难题 里面看看吧!