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〖1/1算式〗
    作业：求算式 ((4-(1.88-3.2*(1/24-1/95))*cos(13)/3)*(1-(24*tan(13)/π))*((1.88-3.2*(1/24-1/95))*cos(13)/(24*tan(13)/π)))^0.5 的值.
    题型：数学计算
    解:
          ((4-(1.88-3.2*(1/24-1/95))*cos(13)/3)*(1-(24*tan(13)/π))*((1.88-3.2*(1/24-1/95))*cos(13)/(24*tan(13)/π)))^0.5
        =((4-(1.88-3.2*0.031141)*cos(13)/3)*(1-(24*tan(13)/π))*((1.88-3.2*(1/24-1/95))*cos(13)/(24*tan(13)/π)))^0.5
        =((4-1.780349*cos(13)/3)*(1-(24*tan(13)/π))*((1.88-3.2*(1/24-1/95))*cos(13)/(24*tan(13)/π)))^0.5
        =((4-1.780349*cos13/3)*(1-(24*tan(13)/π))*((1.88-3.2*(1/24-1/95))*cos(13)/(24*tan(13)/π)))^0.5
        =(3.461476*(1-(24*tan(13)/π))*((1.88-3.2*(1/24-1/95))*cos(13)/(24*tan(13)/π)))^0.5
        =(3.461476*(1-(24*tan13/π))*((1.88-3.2*(1/24-1/95))*cos(13)/(24*tan(13)/π)))^0.5
        =(3.461476*(1-3.53722)*((1.88-3.2*(1/24-1/95))*cos(13)/(24*tan(13)/π)))^0.5
        =(3.461476*(-2.53722)*((1.88-3.2*(1/24-1/95))*cos(13)/(24*tan(13)/π)))^0.5
        =(3.461476*(-2.53722)*((1.88-3.2*0.031141)*cos(13)/(24*tan(13)/π)))^0.5
        =(3.461476*(-2.53722)*(1.780349*cos(13)/(24*tan(13)/π)))^0.5
        =(3.461476*(-2.53722)*(1.780349*cos13/(24*tan(13)/π)))^0.5
        =(3.461476*(-2.53722)*(1.780349*cos13/(24*tan13/π)))^0.5
        =(3.461476*(-2.53722)*(1.780349*cos13/3.53722))^0.5
        =(3.461476*(-2.53722)*0.456735)^0.5
        =-4.011287^0.5
        =-nan
    答案:((4-(1.88-3.2*(1/24-1/95))*cos(13)/3)*(1-(24*tan(13)/π))*((1.88-3.2*(1/24-1/95))*cos(13)/(24*tan(13)/π)))^0.5=-nan
    注：弧度制

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