总述：本次共解1题。其中
           ☆算术计算1题

〖1/1算式〗
    作业：求算式 (2*cos(arctan(tan(13)*cos(arctan(tan(20)/cos(13)))))/(cos(arctan(tan(20)/cos(13)))*sin(arctan(tan(20)/cos(13)))))^0.5 的值.
    题型：数学计算
    解:
          (2*cos(arctan(tan(13)*cos(arctan(tan(20)/cos(13)))))/(cos(arctan(tan(20)/cos(13)))*sin(arctan(tan(20)/cos(13)))))^0.5
        =(2*cos(arctan(tan13*cos(arctan(tan(20)/cos(13)))))/(cos(arctan(tan(20)/cos(13)))*sin(arctan(tan(20)/cos(13)))))^0.5
        =(2*cos(arctan(tan13*cos(arctan(tan20/cos(13)))))/(cos(arctan(tan(20)/cos(13)))*sin(arctan(tan(20)/cos(13)))))^0.5
        =(2*cos(arctan(tan13*cos(arctan(tan20/cos13))))/(cos(arctan(tan(20)/cos(13)))*sin(arctan(tan(20)/cos(13)))))^0.5
        =(2*cos(arctan(tan13*cos(arctan2.465335)))/(cos(arctan(tan(20)/cos(13)))*sin(arctan(tan(20)/cos(13)))))^0.5
        =(2*cos(arctan(tan13*cos1.185451))/(cos(arctan(tan(20)/cos(13)))*sin(arctan(tan(20)/cos(13)))))^0.5
        =(2*cos(arctan0.17404)/(cos(arctan(tan(20)/cos(13)))*sin(arctan(tan(20)/cos(13)))))^0.5
        =(2*cos0.172314/(cos(arctan(tan(20)/cos(13)))*sin(arctan(tan(20)/cos(13)))))^0.5
        =(2*cos0.172314/(cos(arctan(tan20/cos(13)))*sin(arctan(tan(20)/cos(13)))))^0.5
        =(2*cos0.172314/(cos(arctan(tan20/cos13))*sin(arctan(tan(20)/cos(13)))))^0.5
        =(2*cos0.172314/(cos(arctan2.465335)*sin(arctan(tan(20)/cos(13)))))^0.5
        =(2*cos0.172314/(cos1.185451*sin(arctan(tan(20)/cos(13)))))^0.5
        =(2*cos0.172314/(cos1.185451*sin(arctan(tan20/cos(13)))))^0.5
        =(2*cos0.172314/(cos1.185451*sin(arctan(tan20/cos13))))^0.5
        =(2*cos0.172314/(cos1.185451*sin(arctan2.465335)))^0.5
        =(2*cos0.172314/(cos1.185451*sin1.185451))^0.5
        =(2*cos0.172314/0.348315)^0.5
        =5.656897^0.5
        =2.378423217175615
    答案:(2*cos(arctan(tan(13)*cos(arctan(tan(20)/cos(13)))))/(cos(arctan(tan(20)/cos(13)))*sin(arctan(tan(20)/cos(13)))))^0.5=2.378423217175615
    注：弧度制

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