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〖1/1算式〗
    作业：求算式 (-0.01575-0.0203875)^2+(0.0177-0.0203875)^2+(0.0585-0.0203875)^2+(0.0211-0.0203875)^2 的值.
    题型：数学计算
    解:
          (-0.01575-0.0203875)^2+(0.0177-0.0203875)^2+(0.0585-0.0203875)^2+(0.0211-0.0203875)^2
        =-0.036138^2+(0.0177-0.0203875)^2+(0.0585-0.0203875)^2+(0.0211-0.0203875)^2
        =-0.036138^2+(-0.002687)^2+(0.0585-0.0203875)^2+(0.0211-0.0203875)^2
        =-0.036138^2+(-0.002687)^2+0.038113^2+(0.0211-0.0203875)^2
        =-0.036138^2+(-0.002687)^2+0.038113^2+0.000713^2
        =0.001305955044+-0.002687^2+0.038113^2+0.000713^2
        =0.001305955044+0.000007219969+0.038113^2+0.000713^2
        =0.001305955044+0.000007219969+0.001452600769+0.000713^2
        =0.001305955044+0.000007219969+0.001452600769+0.000000508369
        =0.001313+0.001452600769+0.000000508369
        =0.002766+0.000000508369
        =0.002767
    答案:(-0.01575-0.0203875)^2+(0.0177-0.0203875)^2+(0.0585-0.0203875)^2+(0.0211-0.0203875)^2=0.002767

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