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☆算术计算1题
〖1/1算式〗
作业:求算式 sqrt(6)*arctan(sqrt((1.5^2-1)/6))-arctan(sqrt(1.5^2-1))-0.468 的值.
题型:数学计算
解:
sqrt(6)*arctan(sqrt((1.5^2-1)/6))-arctan(sqrt(1.5^2-1))-0.468
=sqrt6*arctan(sqrt((1.5^2-1)/6))-arctan(sqrt(1.5^2-1))-0.468
=sqrt6*arctan(sqrt(1.25/6))-arctan(sqrt(1.5^2-1))-0.468
=sqrt6*arctan(sqrt0.208333)-arctan(sqrt(1.5^2-1))-0.468
=sqrt6*arctan0.456435-arctan(sqrt(1.5^2-1))-0.468
=sqrt6*arctan0.456435-arctan(sqrt1.25)-0.468
=sqrt6*arctan0.456435-arctan1.118034-0.468
=2.44949*arctan0.456435-arctan1.118034-0.468
=2.44949*0.428192-arctan1.118034-0.468
=2.44949*0.428192-0.841069-0.468
=1.048852-0.841069-0.468
=0.207783-0.468
=-0.260217 答案:sqrt(6)*arctan(sqrt((1.5^2-1)/6))-arctan(sqrt(1.5^2-1))-0.468=-0.260217 注:弧度制你的问题在这里没有得到解决?请到 热门难题 里面看看吧!