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〖1/1算式〗
作业:求算式 90-arctan(12.6/2)-arctan(12.6/5)-arctan(12.6/10)+arctan(12.6) 的值.
题型:数学计算
解:
90-arctan(12.6/2)-arctan(12.6/5)-arctan(12.6/10)+arctan(12.6)
=90-arctan6.3-arctan(12.6/5)-arctan(12.6/10)+arctan(12.6)
=90-arctan6.3-arctan2.52-arctan(12.6/10)+arctan(12.6)
=90-arctan6.3-arctan2.52-arctan1.26+arctan(12.6)
=90-arctan6.3-arctan2.52-arctan1.26+arctan12.6
=90-1.413379-arctan2.52-arctan1.26+arctan12.6
=90-1.413379-1.19303-arctan1.26+arctan12.6
=90-1.413379-1.19303-0.899939+arctan12.6
=90-1.413379-1.19303-0.899939+1.491597
=88.586621-1.19303-0.899939+1.491597
=87.393591-0.899939+1.491597
=86.493652+1.491597
=87.985249 答案:90-arctan(12.6/2)-arctan(12.6/5)-arctan(12.6/10)+arctan(12.6)=87.985249 注:弧度制你的问题在这里没有得到解决?请到 热门难题 里面看看吧!