总述:本次共解1题。其中
☆算术计算1题
〖1/1算式〗
作业:求算式 cos(20)*cos20/cos10/cos10/cos30/(1+(sin50*sin18/cos30/cos2)^(1/2)) 的值.
题型:数学计算
解:
cos(20)*cos20/cos10/cos10/cos30/(1+(sin50*sin18/cos30/cos2)^(1/2))
=cos20*cos20/cos10/cos10/cos30/(1+(sin50*sin18/cos30/cos2)^(1/2))
=cos20*cos20/cos10/cos10/cos30/(1+(-3.069586)^(1/2))
=cos20*cos20/cos10/cos10/cos30/(1+(-3.069586)^0.5)
=cos20*cos20/cos10/cos10/cos30/nan
=0.408082*cos20/cos10/cos10/cos30/nan
=0.408082*0.408082/cos10/cos10/cos30/nan
=0.408082*0.408082/-0.839072/cos10/cos30/nan
=0.408082*0.408082/-0.839072/-0.839072/cos30/nan
=0.408082*0.408082/-0.839072/-0.839072/0.154251/nan
=0.166531/(-0.839072)/(-0.839072)/0.154251/
=(-0.19847)/(-0.839072)/0.154251/
=0.236535/0.154251/
=1.533442/
=inf 答案:cos(20)*cos20/cos10/cos10/cos30/(1+(sin50*sin18/cos30/cos2)^(1/2))=inf 注:弧度制你的问题在这里没有得到解决?请到 热门难题 里面看看吧!