总述:本次共解1题。其中
☆算术计算1题
〖1/1算式〗
作业:求算式 (lg100000*lne10+(1/32)^(-1/5))*(tan((arccos-1)/6)*tan(4*(arccos-1)/3)+cos0)/(2/(27^(2/3)-sin(3*(arccos-1)/2))) 的值.
题型:数学计算
解:
(lg100000*lne10+(1/32)^(-1/5))*(tan((arccos-1)/6)*tan(4*(arccos-1)/3)+cos0)/(2/(27^(2/3)-sin(3*(arccos-1)/2)))
=(lg100000*lne10+0.03125^(-1/5))*(tan((arccos-1)/6)*tan(4*(arccos-1)/3)+cos0)/(2/(27^(2/3)-sin(3*(arccos-1)/2)))
=(lg100000*lne10+0.03125^(-0.2))*(tan((arccos-1)/6)*tan(4*(arccos-1)/3)+cos0)/(2/(27^(2/3)-sin(3*(arccos-1)/2)))
=52*(tan((arccos-1)/6)*tan(4*(arccos-1)/3)+cos0)/(2/(27^(2/3)-sin(3*(arccos-1)/2)))
=52*(tan(3.141593/6)*tan(4*(arccos-1)/3)+cos0)/(2/(27^(2/3)-sin(3*(arccos-1)/2)))
=52*(tan0.523599*tan(4*(arccos-1)/3)+cos0)/(2/(27^(2/3)-sin(3*(arccos-1)/2)))
=52*(tan0.523599*tan(4*3.141593/3)+cos0)/(2/(27^(2/3)-sin(3*(arccos-1)/2)))
=52*(tan0.523599*tan4.188791+cos0)/(2/(27^(2/3)-sin(3*(arccos-1)/2)))
=52*2.000003/(2/(27^(2/3)-sin(3*(arccos-1)/2)))
=52*2.000003/(2/(27^0.666667-sin(3*(arccos-1)/2)))
=52*2.000003/(2/(27^0.666667-sin(3*3.141593/2)))
=52*2.000003/(2/(27^0.666667-sin4.712389))
=52*2.000003/(2/10.00001)
=52*2.000003/0.2
=104.000156/0.2
=520.00078 答案:(lg100000*lne10+(1/32)^(-1/5))*(tan((arccos-1)/6)*tan(4*(arccos-1)/3)+cos0)/(2/(27^(2/3)-sin(3*(arccos-1)/2)))=520.00078 注:弧度制你的问题在这里没有得到解决?请到 热门难题 里面看看吧!