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〖1/1算式〗
作业:求算式 (2*3.14/0.1)*sqrt((-0.4*0.1)^2+25*0.01)-(2*3.14/0.1)*5*0.1-6.28 的值.
题型:数学计算
解:
(2*3.14/0.1)*sqrt((-0.4*0.1)^2+25*0.01)-(2*3.14/0.1)*5*0.1-6.28
=62.8*sqrt((-0.4*0.1)^2+25*0.01)-(2*3.14/0.1)*5*0.1-6.28
=62.8*sqrt((-0.04)^2+25*0.01)-(2*3.14/0.1)*5*0.1-6.28
=62.8*sqrt0.2516-(2*3.14/0.1)*5*0.1-6.28
=62.8*sqrt0.2516-62.8*5*0.1-6.28
=62.8*0.501597-62.8*5*0.1-6.28
=31.500292-62.8*5*0.1-6.28
=31.500292-314*0.1-6.28
=31.500292-31.4-6.28
=0.100292-6.28
=-6.179708 答案:(2*3.14/0.1)*sqrt((-0.4*0.1)^2+25*0.01)-(2*3.14/0.1)*5*0.1-6.28=-6.179708你的问题在这里没有得到解决?请到 热门难题 里面看看吧!