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〖1/1算式〗
作业:求算式 (2*3.14/0.1)*sqrt((-0.2*0.1)^2+25*0.01)-(2*3.14/0.1)*5*0.1-6.28 的值.
题型:数学计算
解:
(2*3.14/0.1)*sqrt((-0.2*0.1)^2+25*0.01)-(2*3.14/0.1)*5*0.1-6.28
=62.8*sqrt((-0.2*0.1)^2+25*0.01)-(2*3.14/0.1)*5*0.1-6.28
=62.8*sqrt((-0.02)^2+25*0.01)-(2*3.14/0.1)*5*0.1-6.28
=62.8*sqrt0.2504-(2*3.14/0.1)*5*0.1-6.28
=62.8*sqrt0.2504-62.8*5*0.1-6.28
=62.8*0.5004-62.8*5*0.1-6.28
=31.42512-62.8*5*0.1-6.28
=31.42512-314*0.1-6.28
=31.42512-31.4-6.28
=0.02512-6.28
=-6.25488 答案:(2*3.14/0.1)*sqrt((-0.2*0.1)^2+25*0.01)-(2*3.14/0.1)*5*0.1-6.28=-6.25488你的问题在这里没有得到解决?请到 热门难题 里面看看吧!