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〖1/1算式〗
    作业：求算式 2/3*14300*π*0.45^2*0.7*(sin0.42*π)^3/π+300000*0.00382*0.45*(sin0.42*π+sin0.41*π)/π 的值.
    题型：数学计算
    解:
          2/3*14300*π*0.45^2*0.7*(sin0.42*π)^3/π+300000*0.00382*0.45*(sin0.42*π+sin0.41*π)/π
        =2/3*14300*π*0.45^2*0.7*1.281016^3/π+300000*0.00382*0.45*(sin0.42*π+sin0.41*π)/π
        =2/3*14300*π*0.45^2*0.7*1.281016^3/π+300000*0.00382*0.45*2.533283/π
        =2/3*14300*π*0.2025*0.7*1.281016^3/π+300000*0.00382*0.45*2.533283/π
        =2/3*14300*π*0.2025*0.7*2.102149808111812/π+300000*0.00382*0.45*2.533283/π
        =0.666667*14300*π*0.2025*0.7*2.102149808111812/π+300000*0.00382*0.45*2.533283/π
        =9533.3381*π*0.2025*0.7*2.102149808111812/π+300000*0.00382*0.45*2.533283/π
        =29949.864939*0.2025*0.7*2.102149808111812/π+300000*0.00382*0.45*2.533283/π
        =6064.84765*0.7*2.102149808111812/π+300000*0.00382*0.45*2.533283/π
        =4245.393355*2.102149808111812/π+300000*0.00382*0.45*2.533283/π
        =8924.452827/π+300000*0.00382*0.45*2.533283/π
        =2840.741564+300000*0.00382*0.45*2.533283/π
        =2840.741564+1146*0.45*2.533283/π
        =2840.741564+515.7*2.533283/π
        =2840.741564+1306.414043/π
        =2840.741564+415.844505
        =3256.586069
    答案:2/3*14300*π*0.45^2*0.7*(sin0.42*π)^3/π+300000*0.00382*0.45*(sin0.42*π+sin0.41*π)/π=3256.586069
    注：弧度制

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