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〖1/1算式〗
作业:求算式 1350*670^2*1195*(3-670/1195)*1/6/(20-1350*670*80/3.2/(80+79.990957)^2) 的值.
题型:数学计算
解:
1350*670^2*1195*(3-670/1195)*1/6/(20-1350*670*80/3.2/(80+79.990957)^2)
=1350*670^2*1195*2.439331*1/6/(20-1350*670*80/3.2/(80+79.990957)^2)
=1350*670^2*1195*2.439331*1/6/(20-1350*670*80/3.2/159.990957^2)
=1350*670^2*1195*2.439331*1/6/(-863.400636)
=1350*448900*1195*2.439331*1/6/(-863.400636)
=606015000*1195*2.439331*1/6/(-863.400636)
=724187925000*2.439331*1/6/(-863.400636)
=1766534055278.175049*1/6/(-863.400636)
=1766534055278.175049/6/(-863.400636)
=294422342546.362488/(-863.400636)
=(-341003156.901036) 答案:1350*670^2*1195*(3-670/1195)*1/6/(20-1350*670*80/3.2/(80+79.990957)^2)=-341003156.901036你的问题在这里没有得到解决?请到 热门难题 里面看看吧!