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作业:求算式 12*sin106.12-36*(sin(106.12*2))*(36*(cos106.12)^2+325)^(-1/2) 的值.
题型:数学计算
解:
12*sin106.12-36*(sin(106.12*2))*(36*(cos106.12)^2+325)^(-1/2)
=12*sin106.12-36*(sin212.24)*(36*(cos106.12)^2+325)^(-1/2)
=12*sin106.12-36*(-0.983394)*(36*(cos106.12)^2+325)^(-1/2)
=12*sin106.12-36*(-0.983394)*(36*0.768598^2+325)^(-1/2)
=12*sin106.12-36*(-0.983394)*346.266744^(-1/2)
=12*sin106.12-36*(-0.983394)*346.266744^(-0.5)
=12*-0.639733-36*-0.983394*346.266744^-0.5
=12*-0.639733-36*(-0.983394)*0.053739622132133
=-7.676796-36*(-0.983394)*0.053739622132133
=-7.676796-(-35.402184)*0.053739622132133
=-7.676796-(-1.9025)
=-5.774296 答案:12*sin106.12-36*(sin(106.12*2))*(36*(cos106.12)^2+325)^(-1/2)=-5.774296 注:弧度制你的问题在这里没有得到解决?请到 热门难题 里面看看吧!