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〖1/1算式〗
作业:求算式 28202.4*((240.45^2+108^2)^1.5)/((108^2)*240.45*(1-0.058*ln240.45)) 的值.
题型:数学计算
解:
28202.4*((240.45^2+108^2)^1.5)/((108^2)*240.45*(1-0.058*ln240.45))
=28202.4*(69480.2025^1.5)/((108^2)*240.45*(1-0.058*ln240.45))
=28202.4*18314354.372699446976185/((108^2)*240.45*(1-0.058*ln240.45))
=28202.4*18314354.372699446976185/(11664*240.45*(1-0.058*ln240.45))
=28202.4*18314354.372699446976185/(11664*240.45*0.682014)
=28202.4*18314354.372699446976185/1912782.466123
=516508747760.618896/1912782.466123
=270030.051461 答案:28202.4*((240.45^2+108^2)^1.5)/((108^2)*240.45*(1-0.058*ln240.45))=270030.051461你的问题在这里没有得到解决?请到 热门难题 里面看看吧!