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〖1/1算式〗
    作业：求算式 2*14300*3.14*0.55*0.55*0.57*(sin0.942)^3/9.42 的值.
    题型：数学计算
    解:
          2*14300*3.14*0.55*0.55*0.57*(sin0.942)^3/9.42
        =2*14300*3.14*0.55*0.55*0.57*0.808736^3/9.42
        =2*14300*3.14*0.55*0.55*0.57*0.528956949181792/9.42
        =28600*3.14*0.55*0.55*0.57*0.528956949181792/9.42
        =89804*0.55*0.55*0.57*0.528956949181792/9.42
        =49392.2*0.55*0.57*0.528956949181792/9.42
        =27165.71*0.57*0.528956949181792/9.42
        =15484.4547*0.528956949181792/9.42
        =8190.609918/9.42
        =869.491499
    答案:2*14300*3.14*0.55*0.55*0.57*(sin0.942)^3/9.42=869.491499
    注：弧度制

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