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作业:求算式 2*500/sqrt(3)*ln(0.05/0.05)-350+350*0.05^2/(0.1^2-0.05^2)*(0.1^2/0.05^2-1) 的值.
题型:数学计算
解:
2*500/sqrt(3)*ln(0.05/0.05)-350+350*0.05^2/(0.1^2-0.05^2)*(0.1^2/0.05^2-1)
=2*500/sqrt3*ln(0.05/0.05)-350+350*0.05^2/(0.1^2-0.05^2)*(0.1^2/0.05^2-1)
=2*500/sqrt3*ln1-350+350*0.05^2/(0.1^2-0.05^2)*(0.1^2/0.05^2-1)
=2*500/sqrt3*ln1-350+350*0.05^2/0.0075*(0.1^2/0.05^2-1)
=2*500/sqrt3*ln1-350+350*0.05^2/0.0075*3
=2*500/1.732051*ln1-350+350*0.05^2/0.0075*3
=2*500/1.732051*0-350+350*0.05^2/0.0075*3
=2*500/1.732051*0-350+350*0.0025/0.0075*3
=1000/1.732051*0-350+350*0.0025/0.0075*3
=577.350205*0-350+350*0.0025/0.0075*3
=0-350+350*0.0025/0.0075*3
=0-350+0.875/0.0075*3
=0-350+116.666667*3
=0-350+350.000001
=-350+350.000001
=0.000001 答案:2*500/sqrt(3)*ln(0.05/0.05)-350+350*0.05^2/(0.1^2-0.05^2)*(0.1^2/0.05^2-1)=0.000001你的问题在这里没有得到解决?请到 热门难题 里面看看吧!