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作业:求算式 (4.5-tan30)*sin(45-21.06/2)/sin(45+21.06/2+30)+1/cos30+1.5 的值.
题型:数学计算
解:
(4.5-tan30)*sin(45-21.06/2)/sin(45+21.06/2+30)+1/cos30+1.5
=10.905331*sin(45-21.06/2)/sin(45+21.06/2+30)+1/cos30+1.5
=10.905331*sin34.47/sin(45+21.06/2+30)+1/cos30+1.5
=10.905331*sin34.47/sin85.53+1/cos30+1.5
=10.905331*0.087408/sin85.53+1/cos30+1.5
=10.905331*0.087408/-0.649555+1/cos30+1.5
=10.905331*0.087408/-0.649555+1/0.154251+1.5
=0.953213/(-0.649555)+1/0.154251+1.5
=(-1.467486)+1/0.154251+1.5
=-1.467486+6.48294+1.5
=5.015454+1.5
=6.515454 答案:(4.5-tan30)*sin(45-21.06/2)/sin(45+21.06/2+30)+1/cos30+1.5=6.515454 注:弧度制你的问题在这里没有得到解决?请到 热门难题 里面看看吧!