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☆算术计算1题
〖1/1算式〗
作业:求算式 -(100/500)*log(2,100/500)-(300/500)*log(2,300/500)-(100/500)*log(2,100/500) 的值.
题型:数学计算
解:
-(100/500)*log(2,100/500)-(300/500)*log(2,300/500)-(100/500)*log(2,100/500)
=-0.2*log(2,100/500)-(300/500)*log(2,300/500)-(100/500)*log(2,100/500)
=-0.2*(-2.321928)-(300/500)*log(2,300/500)-(100/500)*log(2,100/500)
=-0.2*(-2.321928)-0.6*log(2,300/500)-(100/500)*log(2,100/500)
=-0.2*(-2.321928)-0.6*(-0.736966)-(100/500)*log(2,100/500)
=-0.2*(-2.321928)-0.6*(-0.736966)-0.2*log(2,100/500)
=-0.2*(-2.321928)-0.6*(-0.736966)-0.2*(-2.321928)
=0.464386-0.6*(-0.736966)-0.2*(-2.321928)
=0.464386-(-0.44218)-0.2*(-2.321928)
=0.464386--0.44218-(-0.464386)
=0.906566-(-0.464386)
=1.370952 答案:-(100/500)*log(2,100/500)-(300/500)*log(2,300/500)-(100/500)*log(2,100/500)=1.370952你的问题在这里没有得到解决?请到 热门难题 里面看看吧!