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〖1/1算式〗
作业:求算式 1925.4*(sin1.32)^3/3.14+295.44*(sin1.32+sin1.29)/3.14 的值.
题型:数学计算
解:
1925.4*(sin1.32)^3/3.14+295.44*(sin1.32+sin1.29)/3.14
=1925.4*0.968715^3/3.14+295.44*(sin1.32+sin1.29)/3.14
=1925.4*0.968715^3/3.14+295.44*1.92955/3.14
=1925.4*0.909050633442926/3.14+295.44*1.92955/3.14
=1750.28609/3.14+295.44*1.92955/3.14
=557.415952+295.44*1.92955/3.14
=557.415952+570.066252/3.14
=557.415952+181.549762
=738.965714 答案:1925.4*(sin1.32)^3/3.14+295.44*(sin1.32+sin1.29)/3.14=738.965714 注:弧度制你的问题在这里没有得到解决?请到 热门难题 里面看看吧!