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〖1/1算式〗
作业:求算式 0.56*50*3/(1+1/0.9)^0.45+0.35*103*10^(-2)/(1+1/0.9)^0.2 的值.
题型:数学计算
解:
0.56*50*3/(1+1/0.9)^0.45+0.35*103*10^(-2)/(1+1/0.9)^0.2
=0.56*50*3/2.111111^0.45+0.35*103*10^(-2)/(1+1/0.9)^0.2
=0.56*50*3/2.111111^0.45+0.35*103*10^(-2)/(1+1/0.9)^0.2
=0.56*50*3/2.111111^0.45+0.35*103*10^-2/2.111111^0.2
=0.56*50*3/1.399683944406222+0.35*103*10^(-2)/2.111111^0.2
=0.56*50*3/1.399683944406222+0.35*103*0.01/2.111111^0.2
=0.56*50*3/1.399683944406222+0.35*103*0.01/1.161187130110139
=28*3/1.399683944406222+0.35*103*0.01/1.161187130110139
=84/1.399683944406222+0.35*103*0.01/1.161187130110139
=60.013548+0.35*103*0.01/1.161187130110139
=60.013548+36.05*0.01/1.161187130110139
=60.013548+0.3605/1.161187130110139
=60.013548+0.310458
=60.324006 答案:0.56*50*3/(1+1/0.9)^0.45+0.35*103*10^(-2)/(1+1/0.9)^0.2=60.324006你的问题在这里没有得到解决?请到 热门难题 里面看看吧!