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☆算术计算1题
〖1/1算式〗
作业:求算式 0.064^(-1/3)+16^(-3/4)+(256/25)^(-1/2)+(2^3)^(-4/3) 的值.
题型:数学计算
解:
0.064^(-1/3)+16^(-3/4)+(256/25)^(-1/2)+(2^3)^(-4/3)
=0.064^(-0.333333)+16^(-3/4)+(256/25)^(-1/2)+(2^3)^(-4/3)
=0.064^-0.333333+16^(-0.75)+(256/25)^(-1/2)+(2^3)^(-4/3)
=0.064^-0.333333+16^-0.75+10.24^(-1/2)+(2^3)^(-4/3)
=0.064^-0.333333+16^-0.75+10.24^(-0.5)+(2^3)^(-4/3)
=0.064^-0.333333+16^-0.75+10.24^-0.5+8^(-4/3)
=0.064^-0.333333+16^-0.75+10.24^-0.5+8^(-1.333333)
=2.49999770927422+16^(-0.75)+10.24^(-0.5)+8^(-1.333333)
=2.49999770927422+0.125+10.24^(-0.5)+8^(-1.333333)
=2.49999770927422+0.125+0.3125+8^(-1.333333)
=2.49999770927422+0.125+0.3125+0.062500043321714
=2.624998+0.3125+0.062500043321714
=2.937498+0.062500043321714
=2.999998 答案:0.064^(-1/3)+16^(-3/4)+(256/25)^(-1/2)+(2^3)^(-4/3)=2.999998你的问题在这里没有得到解决?请到 热门难题 里面看看吧!