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〖1/1算式〗
作业:求算式 (0.825+0.387*(9.34*10^8)^(1/6)/(1+(0.492/0.6974)^(9/16))^(8/27))^2 的值.
题型:数学计算
解:
(0.825+0.387*(9.34*10^8)^(1/6)/(1+(0.492/0.6974)^(9/16))^(8/27))^2
=(0.825+0.387*934000000^(1/6)/(1+(0.492/0.6974)^(9/16))^(8/27))^2
=(0.825+0.387*934000000^0.166667/(1+(0.492/0.6974)^(9/16))^(8/27))^2
=(0.825+0.387*934000000^0.166667/(1+0.705477^(9/16))^(8/27))^2
=(0.825+0.387*934000000^0.166667/(1+0.705477^0.5625)^(8/27))^2
=(0.825+0.387*934000000^0.166667/1.82181^(8/27))^2
=(0.825+0.387*934000000^0.166667/1.82181^0.296296)^2
=10.954447^2
=119.999909075809001 答案:(0.825+0.387*(9.34*10^8)^(1/6)/(1+(0.492/0.6974)^(9/16))^(8/27))^2=119.999909075809001你的问题在这里没有得到解决?请到 热门难题 里面看看吧!