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〖1/1算式〗
作业:求算式 (0.5*(e^(3.3072)+e^(-3.3072))*0.5*(e^(3.3072)-e^(-3.3072))-sin(3.3072)*cos(3.3072))*0.5 的值.
题型:数学计算
解:
(0.5*(e^(3.3072)+e^(-3.3072))*0.5*(e^(3.3072)-e^(-3.3072))-sin(3.3072)*cos(3.3072))*0.5
=(0.5*(e^3.3072+e^(-3.3072))*0.5*(e^(3.3072)-e^(-3.3072))-sin(3.3072)*cos(3.3072))*0.5
=(0.5*(e^3.3072+e^(-3.3072))*0.5*(e^(3.3072)-e^(-3.3072))-sin(3.3072)*cos(3.3072))*0.5
=(0.5*27.345179*0.5*(e^(3.3072)-e^(-3.3072))-sin(3.3072)*cos(3.3072))*0.5
=(0.5*27.345179*0.5*(e^3.3072-e^(-3.3072))-sin(3.3072)*cos(3.3072))*0.5
=(0.5*27.345179*0.5*(e^3.3072-e^(-3.3072))-sin(3.3072)*cos(3.3072))*0.5
=(0.5*27.345179*0.5*27.271942-sin(3.3072)*cos(3.3072))*0.5
=(0.5*27.345179*0.5*27.271942-sin3.3072*cos(3.3072))*0.5
=(0.5*27.345179*0.5*27.271942-sin3.3072*cos3.3072)*0.5
=186.276445*0.5
=93.138222 答案:(0.5*(e^(3.3072)+e^(-3.3072))*0.5*(e^(3.3072)-e^(-3.3072))-sin(3.3072)*cos(3.3072))*0.5=93.138222 注:弧度制你的问题在这里没有得到解决?请到 热门难题 里面看看吧!