总述:本次共解1题。其中
☆算术计算1题
〖1/1算式〗
作业:求算式 ((cos(3.3072))^2)+(0.5*(e^(3.3072)+e^(-3.3072)))^2 的值.
题型:数学计算
解:
((cos(3.3072))^2)+(0.5*(e^(3.3072)+e^(-3.3072)))^2
=((cos3.3072)^2)+(0.5*(e^(3.3072)+e^(-3.3072)))^2
=((-0.986318)^2)+(0.5*(e^(3.3072)+e^(-3.3072)))^2
=0.972823197124+(0.5*(e^(3.3072)+e^(-3.3072)))^2
=0.972823197124+(0.5*(e^3.3072+e^(-3.3072)))^2
=0.972823197124+(0.5*(e^3.3072+e^(-3.3072)))^2
=0.972823197124+(0.5*27.345179)^2
=0.972823197124+13.67259^2
=0.972823197124+186.939717308100001
=187.912541 答案:((cos(3.3072))^2)+(0.5*(e^(3.3072)+e^(-3.3072)))^2=187.912541 注:弧度制你的问题在这里没有得到解决?请到 热门难题 里面看看吧!