总述:本次共解1题。其中
☆算术计算1题
〖1/1算式〗
作业:求算式 log(log(log(2,1),log(2,2)),log(log(2,3),log(2,4))) 的值.
题型:数学计算
解:
log(log(log(2,1),log(2,2)),log(log(2,3),log(2,4)))
=log(log(0,log(2,2)),log(log(2,3),log(2,4)))
=log(log(0,1),log(log(2,3),log(2,4)))
=log(0,log(log(2,3),log(2,4)))
=log(0,log(1.584963,log(2,4)))
=log(0,log(1.584963,2))
=log(0,1.505006)
=0 答案:log(log(log(2,1),log(2,2)),log(log(2,3),log(2,4)))=0你的问题在这里没有得到解决?请到 热门难题 里面看看吧!