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〖1/1算式〗
作业:求算式 10^(6.078-1343.94/(1+219.58))+10^(6.032-1206/(1+220.4))-2 的值.
题型:数学计算
解:
10^(6.078-1343.94/(1+219.58))+10^(6.032-1206/(1+220.4))-2
=10^(6.078-1343.94/220.58)+10^(6.032-1206/(1+220.4))-2
=10^(-0.014755)+10^(6.032-1206/(1+220.4))-2
=10^-0.014755+10^(6.032-1206/221.4)-2
=10^-0.014755+10^0.584846-2
=0.966596014256341+10^0.584846-2
=0.966596014256341+3.844554307048949-2
=4.81115-2
=2.81115 答案:10^(6.078-1343.94/(1+219.58))+10^(6.032-1206/(1+220.4))-2=2.81115你的问题在这里没有得到解决?请到 热门难题 里面看看吧!