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〖1/1算式〗
作业:求算式 4000*(1.02^10+1.02^9+1.02^8+1.02^7+1.02^6+1.02^5+1.02^4+1.02^3+1.02^2+1.02+1) 的值.
题型:数学计算
解:
4000*(1.02^10+1.02^9+1.02^8+1.02^7+1.02^6+1.02^5+1.02^4+1.02^3+1.02^2+1.02+1)
=4000*12.168715
=48674.86 答案:4000*(1.02^10+1.02^9+1.02^8+1.02^7+1.02^6+1.02^5+1.02^4+1.02^3+1.02^2+1.02+1)=48674.86你的问题在这里没有得到解决?请到 热门难题 里面看看吧!