总述:本次共解1题。其中
☆算术计算1题
〖1/1算式〗
作业:求算式 1×1×1.1×0.45×10^(-3)×200×1230*√((2+0.6×0.618)*√35×0.00201×330)+0.75×10^(-3)×330×(1520+509)×0.707 的值.
题型:数学计算
解:
1×1×1.1×0.45×10^(-3)×200×1230*√((2+0.6×0.618)*√35×0.00201×330)+0.75×10^(-3)×330×(1520+509)×0.707
=1×1×1.1×0.45×10^(-3)×200×1230*√((2+0.6×0.618)*√35×0.00201×330)+0.75×10^(-3)×330×(1520+509)×0.707
=1×1×1.1×0.45×10^-3×200×1230*√(2.3708*√35×0.00201×330)+0.75×10^(-3)×330×(1520+509)×0.707
=1×1×1.1×0.45×10^-3×200×1230*√9.30336+0.75×10^(-3)×330×(1520+509)×0.707
=1×1×1.1×0.45×10^-3×200×1230*√9.30336+0.75×10^(-3)×330×(1520+509)×0.707
=1×1×1.1×0.45×10^-3×200×1230*√9.30336+0.75×10^-3×330×2029×0.707
=1×1×1.1×0.45×10^-3×200×1230*3.050141+0.75×10^-3×330×2029×0.707
=1×1×1.1×0.45×0.001×200×1230*3.050141+0.75×10^(-3)×330×2029×0.707
=1×1×1.1×0.45×0.001×200×1230*3.050141+0.75×0.001×330×2029×0.707
=1×1.1×0.45×0.001×200×1230*3.050141+0.75×0.001×330×2029×0.707
=1.1×0.45×0.001×200×1230*3.050141+0.75×0.001×330×2029×0.707
=0.495×0.001×200×1230*3.050141+0.75×0.001×330×2029×0.707
=0.000495×200×1230*3.050141+0.75×0.001×330×2029×0.707
=0.099×1230*3.050141+0.75×0.001×330×2029×0.707
=121.77*3.050141+0.75×0.001×330×2029×0.707
=371.41567+0.75×0.001×330×2029×0.707
=371.41567+0.00075×330×2029×0.707
=371.41567+0.2475×2029×0.707
=371.41567+502.1775×0.707
=371.41567+355.039492
=726.455162 答案:1×1×1.1×0.45×10^(-3)×200×1230*√((2+0.6×0.618)*√35×0.00201×330)+0.75×10^(-3)×330×(1520+509)×0.707=726.455162你的问题在这里没有得到解决?请到 热门难题 里面看看吧!