总述:本次共解1题。其中
☆算术计算1题
〖1/1算式〗
作业:求算式 1×1×1.1×0.45×10^(-3)×200×1449*√((2+0.6×0.217)*√35×0.00201×250) 的值.
题型:数学计算
解:
1×1×1.1×0.45×10^(-3)×200×1449*√((2+0.6×0.217)*√35×0.00201×250)
=1×1×1.1×0.45×10^(-3)×200×1449*√((2+0.6×0.217)*√35×0.00201×250)
=1×1×1.1×0.45×10^-3×200×1449*√(2.1302*√35×0.00201×250)
=1×1×1.1×0.45×10^-3×200×1449*√6.33275
=1×1×1.1×0.45×10^-3×200×1449*2.516496
=1×1×1.1×0.45×0.001×200×1449*2.516496
=1×1.1×0.45×0.001×200×1449*2.516496
=1.1×0.45×0.001×200×1449*2.516496
=0.495×0.001×200×1449*2.516496
=0.000495×200×1449*2.516496
=0.099×1449*2.516496
=143.451*2.516496
=360.993868 答案:1×1×1.1×0.45×10^(-3)×200×1449*√((2+0.6×0.217)*√35×0.00201×250)=360.993868你的问题在这里没有得到解决?请到 热门难题 里面看看吧!