总述:本次共解1题。其中
☆算术计算1题
〖1/1算式〗
作业:求算式 1×1×1.1×0.45×10^(-3)×200×1242*√((2+0.6×0.303)*√35×0.00201×330) 的值.
题型:数学计算
解:
1×1×1.1×0.45×10^(-3)×200×1242*√((2+0.6×0.303)*√35×0.00201×330)
=1×1×1.1×0.45×10^(-3)×200×1242*√((2+0.6×0.303)*√35×0.00201×330)
=1×1×1.1×0.45×10^-3×200×1242*√(2.1818*√35×0.00201×330)
=1×1×1.1×0.45×10^-3×200×1242*√8.56152
=1×1×1.1×0.45×10^-3×200×1242*2.926008
=1×1×1.1×0.45×0.001×200×1242*2.926008
=1×1.1×0.45×0.001×200×1242*2.926008
=1.1×0.45×0.001×200×1242*2.926008
=0.495×0.001×200×1242*2.926008
=0.000495×200×1242*2.926008
=0.099×1242*2.926008
=122.958*2.926008
=359.776092 答案:1×1×1.1×0.45×10^(-3)×200×1242*√((2+0.6×0.303)*√35×0.00201×330)=359.776092你的问题在这里没有得到解决?请到 热门难题 里面看看吧!