总述:本次共解1题。其中
☆算术计算1题
〖1/1算式〗
作业:求算式 1×1×1.1×0.45×10^(-3)×200×1449*√((2+0.6×0.22)*√30×0.00201×250)+0.75×10^(-3)×330×(628+509)×0.707 的值.
题型:数学计算
解:
1×1×1.1×0.45×10^(-3)×200×1449*√((2+0.6×0.22)*√30×0.00201×250)+0.75×10^(-3)×330×(628+509)×0.707
=1×1×1.1×0.45×10^(-3)×200×1449*√((2+0.6×0.22)*√30×0.00201×250)+0.75×10^(-3)×330×(628+509)×0.707
=1×1×1.1×0.45×10^-3×200×1449*√(2.132*√30×0.00201×250)+0.75×10^(-3)×330×(628+509)×0.707
=1×1×1.1×0.45×10^-3×200×1449*√5.868+0.75×10^(-3)×330×(628+509)×0.707
=1×1×1.1×0.45×10^-3×200×1449*√5.868+0.75×10^(-3)×330×(628+509)×0.707
=1×1×1.1×0.45×10^-3×200×1449*√5.868+0.75×10^-3×330×1137×0.707
=1×1×1.1×0.45×10^-3×200×1449*2.422396+0.75×10^-3×330×1137×0.707
=1×1×1.1×0.45×0.001×200×1449*2.422396+0.75×10^(-3)×330×1137×0.707
=1×1×1.1×0.45×0.001×200×1449*2.422396+0.75×0.001×330×1137×0.707
=1×1.1×0.45×0.001×200×1449*2.422396+0.75×0.001×330×1137×0.707
=1.1×0.45×0.001×200×1449*2.422396+0.75×0.001×330×1137×0.707
=0.495×0.001×200×1449*2.422396+0.75×0.001×330×1137×0.707
=0.000495×200×1449*2.422396+0.75×0.001×330×1137×0.707
=0.099×1449*2.422396+0.75×0.001×330×1137×0.707
=143.451*2.422396+0.75×0.001×330×1137×0.707
=347.495129+0.75×0.001×330×1137×0.707
=347.495129+0.00075×330×1137×0.707
=347.495129+0.2475×1137×0.707
=347.495129+281.4075×0.707
=347.495129+198.955103
=546.450232 答案:1×1×1.1×0.45×10^(-3)×200×1449*√((2+0.6×0.22)*√30×0.00201×250)+0.75×10^(-3)×330×(628+509)×0.707=546.450232你的问题在这里没有得到解决?请到 热门难题 里面看看吧!